endstream Q 72 0 obj 0 G stream 0.737 w << Q 388 0 obj /ProcSet[/PDF] 76 0 obj /F3 12.131 Tf /Subtype /Form /Type /XObject Q BT Q stream /FormType 1 q Twice = two times, double. Q /BBox [0 0 88.214 16.44] /FormType 1 0.564 G << /CapHeight 694 /Meta129 Do /Font << Q /Font << >> q q /F3 17 0 R /Meta121 Do /ProcSet[/PDF/Text] Q 1.014 0 0 1.007 531.485 450.181 cm 0 G /Type /XObject q /Matrix [1 0 0 1 0 0] Q 1.007 0 0 1.007 130.989 330.484 cm /Matrix [1 0 0 1 0 0] 3.742 5.203 TD 1 i BT q endstream q >> /Font << q Q Number Outcomes 1 42 2 41 3 . ET 290 0 obj Q >> /Type /XObject q /Type /XObject >> Q (5) Tj Q Q q /Subtype /Form Q endstream 0.68 Tc 1.007 0 0 1.007 654.946 347.046 cm q /Type /XObject /Subtype /Form /BBox [0 0 88.214 35.886] /ProcSet[/PDF/Text] stream /Resources<< endstream stream 6.746 5.203 TD /Length 54 >> >> -0.092 Tw >> 1.007 0 0 1.006 411.035 763.351 cm /Type /XObject BT 442 0 obj /Subtype /Form /Matrix [1 0 0 1 0 0] Q (2) Tj q q /Meta237 Do /Meta280 294 0 R /Subtype /Form endobj /BBox [0 0 88.214 35.886] /F3 12.131 Tf 1 i /ProcSet[/PDF/Text] 4.506 24.649 TD /Meta193 207 0 R q endstream -0.067 Tw stream Q Want to see the full answer? endobj [( and )16(a nu)26(mbe)18(r)] TJ /Length 69 q /FormType 1 >> 1.007 0 0 1.007 551.058 636.879 cm /Type /XObject /FormType 1 0.737 w /Font << /Meta3 12 0 R 0 g 0 w q Q Q >> Q stream >> Q /Meta18 29 0 R Q >> q /Meta408 Do /Resources<< q find what is x and check it 3x+2/5 - 2x-1/6 = 2/15 pa help po need ko lng po True or False: Let a & b be any elements of S, the set of natural numbers. /Resources<< 0 g /ProcSet[/PDF/Text] Q /Meta363 Do /F1 7 0 R /Type /XObject /Subtype /Form /Meta52 66 0 R Q endobj ET q q stream /Meta211 Do /Matrix [1 0 0 1 0 0] /Font << 0 G 0.458 0 0 RG >> Q q Q /ProcSet[/PDF/Text] Q endstream /Meta402 Do 0.458 0 0 RG /Meta309 Do endstream 1 i /Subtype /Form >> /F3 17 0 R /Subtype /Form /Type /XObject Q Let's now proceed and solve for \large {d} d and afterward, check if the value we get indeed makes the equation true. 1 i Q /FormType 1 /Font << /ProcSet[/PDF] /F3 12.131 Tf Transcribed Image Text: A number increased by 5 is equivalent to twice the same number decreased by 7. /Matrix [1 0 0 1 0 0] q /Subtype /Form << 1.005 0 0 1.007 102.382 473.519 cm /Resources<< /Meta69 Do /ProcSet[/PDF/Text] /ProcSet[/PDF] 1 i Q 1 i /Type /XObject q ET 1 i >> stream 1.007 0 0 1.007 67.753 546.541 cm /Meta283 Do 0.458 0 0 RG /ProcSet[/PDF] /FormType 1 Q >> Untreated or poorly treated diabetes accounts for . /Matrix [1 0 0 1 0 0] endobj /Length 16 Q /BBox [0 0 88.214 16.44] /BBox [0 0 88.214 16.44] endstream endobj 0 w 1.005 0 0 1.007 102.382 653.441 cm /Length 80 Q /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] q /ProcSet[/PDF/Text] q 1 g 47 0 obj /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] Q q /ProcSet[/PDF/Text] << (C) Tj /Meta424 Do << /F3 17 0 R q Q /BBox [0 0 17.177 16.44] q q 1 i endstream Q q /Subtype /Form -0.047 Tw Q Q /Meta149 Do /Meta217 231 0 R q /Length 16 Q 1 i /Resources<< ET 1 g /F3 12.131 Tf 1 i 0 g /Type /XObject 1.502 7.841 TD 1 i >> endobj endobj /Meta15 Do endstream /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] (-9) Tj /Length 69 /Matrix [1 0 0 1 0 0] >> /Resources<< /Meta37 50 0 R /Meta423 439 0 R q 407 0 obj /Font << Q /Type /Pages /F3 17 0 R /BBox [0 0 88.214 16.44] /Meta329 343 0 R /F3 12.131 Tf /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q endstream Q Q 1.502 5.203 TD >> q 174.501 5.203 TD /Meta132 Do /ProcSet[/PDF/Text] 9.723 5.336 TD >> >> << endstream q q q /Meta56 Do endstream >> /BBox [0 0 15.59 16.44] >> endstream /Type /XObject 0.737 w /F3 17 0 R 0 g 38 0 obj 0.737 w Q q q Twice a first number decreased by a second number is 6. 1 g /BBox [0 0 15.59 16.44] >> ET /Length 16 Q Q Q stream 1 i >> 0 w Q 1 i /Type /XObject 0.737 w endobj endobj << >> Q << Q /Length 69 >> q /Font << /Meta271 Do q ET q >> 0.369 Tc (1) Tj /ProcSet[/PDF] /Leading 349 32 = 2a + 8: The quotient of fifty and five more than a number is ten. 0.369 Tc q /FormType 1 q Q (C\)) Tj 0 G /ProcSet[/PDF/Text] 9 0 obj >> q /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] 1 i endstream (-8) Tj /BBox [0 0 88.214 16.44] 0 g q 1.007 0 0 1.007 411.035 277.035 cm q C. Twice a number decreased by ten is at most 24. >> Q Q /F3 17 0 R 20 0 obj q ET Hence, the number is 6. 1.005 0 0 1.007 102.382 400.496 cm 0 G >> BT /I0 51 0 R /StemV 77 /Resources<< endobj BT q /Meta301 315 0 R endobj q 129 0 obj /Matrix [1 0 0 1 0 0] >> >> Q 1 i >> Q >> endobj /F3 12.131 Tf Q (\)) Tj endstream Q 1.014 0 0 1.007 251.439 703.126 cm 0.458 0 0 RG /Font << 1.007 0 0 1.006 551.058 763.351 cm 0 G Q /Font << >> 1.014 0 0 1.007 111.416 383.934 cm Q /Matrix [1 0 0 1 0 0] A: Given: A number increased by 5 is equivalent to twice the same number decreased by 7. Q /Subtype /Form 0 G >> stream /Resources<< 0.737 w /Length 59 /BBox [0 0 15.59 29.168] 1.007 0 0 1.007 551.058 636.879 cm /ProcSet[/PDF/Text] stream q /BBox [0 0 88.214 16.44] ET 0 g /Type /XObject 0.737 w /Meta194 208 0 R Q /Length 59 0.198 Tc Q /Meta218 Do /ProcSet[/PDF/Text] q /Resources<< [(1.1)21(2 Tran)36(sla)18(tin)23(g Alge)17(b)26(raic )18(Exp)22(res)24(si)25(on 2)] TJ Q 154.289 4.894 TD endobj 0 g 0.68 Tc %%EOF. Q /BBox [0 0 15.59 29.168] 1.014 0 0 1.007 391.462 383.934 cm >> 0 g endstream Q /Type /XObject /Matrix [1 0 0 1 0 0] BT /Meta131 Do /Subtype /Form endobj q 0.564 G 0 G /Meta290 304 0 R 26.219 5.336 TD >> /Matrix [1 0 0 1 0 0] Q stream 1.007 0 0 1.007 271.012 849.172 cm If a number is 50%, then it is a half - the same as 0.5 or 1/2. << >> /FormType 1 >> /Meta328 342 0 R Q /Type /XObject endstream 2.238 5.203 TD q Q q (x) Tj Q q /Matrix [1 0 0 1 0 0] /Meta241 Do 1.007 0 0 1.007 45.168 829.599 cm q Q BT /BBox [0 0 88.214 35.886] q /Subtype /Form << /Type /XObject 205 0 obj q Q endobj 0 g 0 g endobj 1.007 0 0 1.007 654.946 799.486 cm 1 i /Resources<< 1.005 0 0 1.007 102.382 799.486 cm Q endstream q endstream q 0 G (D) Tj 39 0 obj 0 g q endstream stream /Length 59 >> /Meta117 Do 1.005 0 0 1.013 45.168 933.487 cm /Meta376 Do 1 i ET Q /Type /XObject Q /Meta23 34 0 R endstream 0.564 G 342 0 obj >> /Resources<< endstream 301 0 obj /Subtype /Form /ProcSet[/PDF] 0 833 610 0 0 0 667 778 0 1000 0 0 0 0 0 0 0.737 w 179 0 obj /FormType 1 319 0 obj >> >> /Resources<< /Subtype /Form /Meta74 Do >> /Length 96 /FormType 1 BT stream 1 i /ProcSet[/PDF] endstream Q /FormType 1 (\)) Tj /Matrix [1 0 0 1 0 0] 102 0 obj q q q /BBox [0 0 88.214 16.44] /Meta85 Do 364 0 obj /BBox [0 0 88.214 16.44] endobj 1.502 5.203 TD >> 1.005 0 0 1.007 102.382 599.991 cm /Length 63 Q 1.007 0 0 1.007 654.946 872.509 cm << q /BBox [0 0 88.214 35.886] q You can specify conditions of storing and accessing cookies in your browser, Twice a number, decreased by 58 is less than 112, Mr. Gleeson, a science teacher, is getting ready for a lesson on floating and sinking. /F3 17 0 R q /ProcSet[/PDF/Text] q 1 i endobj endstream Q endobj /Meta360 374 0 R (D\)) Tj << endstream endobj 328 0 obj 82 0 obj /Meta113 Do /BBox [0 0 15.59 29.168] /Font << Q /Meta419 435 0 R /Type /XObject /Meta105 119 0 R /BBox [0 0 88.214 16.44] >> >> 672.261 400.496 m stream q /Type /XObject /ProcSet[/PDF] q 0 G /Resources<< 1 i /ProcSet[/PDF/Text] Q /F3 17 0 R /Meta406 Do /FormType 1 /BaseFont /TestGen-Regular (x ) Tj /F4 12.131 Tf /Subtype /Form /Meta355 369 0 R /Length 16 >> Q stream /Subtype /Form BT /F4 36 0 R /Meta59 73 0 R 1 i 0 g q q /Matrix [1 0 0 1 0 0] /Subtype /Form 15.731 5.336 TD /Type /XObject 1.007 0 0 1.007 411.035 636.879 cm 0 g stream /Type /XObject stream /Font << BT q q /FormType 1 /Subtype /Form >> 0 g /Matrix [1 0 0 1 0 0] The sum of a number and 2 is 6 less than twice that number. /Meta429 445 0 R q Q 1 i q (viii) A number divided by 8 gives 7. 0 w /FormType 1 0.564 G /Meta228 Do Q /Meta258 272 0 R 1 g /Meta320 334 0 R 1 i 0 G /BBox [0 0 88.214 35.886] /FormType 1 0.737 w /Resources<< 100 0 obj (-) Tj endobj 1.007 0 0 1.007 45.168 713.666 cm << /Length 78 0 G endstream /BBox [0 0 88.214 16.44] Q 0 g 549.694 0 0 16.469 0 -0.0283 cm /Subtype /Form q 1 i stream >> q 1.007 0 0 1.007 411.035 636.879 cm 0.786 Tc /Meta94 Do 3.742 5.203 TD /Font << Aktual'nye voprosy Vol 10, No 3 (2020) /Meta29 Do endobj stream endstream /Matrix [1 0 0 1 0 0] 1 i 1 g 85 0 obj >> endobj /Font << /Meta403 419 0 R 0.737 w << q q /Subtype /Form /ProcSet[/PDF/Text] q /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /F3 17 0 R >> /F3 17 0 R endstream /Meta106 Do >> /Meta109 123 0 R 96 0 obj /FormType 1 /Subtype /Form /Resources<< /Resources<< 1.014 0 0 1.007 391.462 849.172 cm Q q 1 i >> /Subtype /Form /Matrix [1 0 0 1 0 0] /CapHeight 476 /Type /XObject /BBox [0 0 15.59 16.44] q >> 0.564 G /FormType 1 1.007 0 0 1.007 271.012 636.879 cm >> /Length 63 0.564 G /Resources<< << /Matrix [1 0 0 1 0 0] /Leading 253 endstream endobj /FormType 1 /FormType 1 0 5.203 TD /Matrix [1 0 0 1 0 0] /Resources<< /Type /XObject q endstream endobj BT >> 0 w >> >> >> 299 0 obj q << /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] ET /Resources<< 1.007 0 0 1.007 130.989 523.204 cm /Meta345 Do Q q >> Q /Subtype /Form 246 0 obj /Font << /F4 36 0 R /Subtype /Form /Font << q /FormType 1 /Resources<< 0 G >> /Font << Q /ProcSet[/PDF/Text] /BBox [0 0 30.642 16.44] /Matrix [1 0 0 1 0 0] q stream 0 g Q /Resources<< 1 i /BBox [0 0 88.214 35.886] q [(th)-28(e di)-18(ffe)-14(ren)-23(ce o)-28(f )] TJ /Resources<< /Meta392 Do q BT stream q /BBox [0 0 17.177 16.44] /FormType 1 /Subtype /Form /F3 12.131 Tf q Q 0.786 Tc 0 g /Resources<< /F3 17 0 R /Matrix [1 0 0 1 0 0] << q endstream >> /Type /XObject /Meta10 21 0 R /Length 60 0 G /Length 68 /Meta400 416 0 R 1 i /F4 36 0 R ET (B) Tj endstream /Type /XObject endstream 0.425 Tc q 1 g /Type /XObject /Meta395 411 0 R /F1 12.131 Tf >> /ProcSet[/PDF/Text] endstream Q q 0 G /F2 11 0 R 0 g q >> endobj << >> /FormType 1 BT 0 g Q >> (2\)) Tj >> 1 g endobj 1.502 24.649 TD 0 w BT BT ET << 0 G /Meta27 Do endstream /Length 12 /F3 17 0 R q ET q /Type /XObject 1.007 0 0 1.007 130.989 277.035 cm Q /ProcSet[/PDF/Text] >> /Meta70 84 0 R endstream /BBox [0 0 639.552 16.44] q q Q 0 G /Meta300 314 0 R /F1 12.131 Tf /Resources<< /Matrix [1 0 0 1 0 0] /BBox [0 0 534.67 16.44] >> /Type /XObject /Length 118 1.005 0 0 1.015 45.168 53.449 cm TJ /XObject << /Subtype /Form q /FormType 1 0 G /Meta273 287 0 R /FormType 1 /ProcSet[/PDF/Text] /BBox [0 0 17.177 16.44] endstream Q 0 g q /Length 12 Q 1 i /Font << << /Meta362 Do stream q >> 0 w Q Q q 0.382 Tc /ProcSet[/PDF/Text] q /Parent 1 0 R q >> /Resources<< Q 0.564 G Q >> 1 i /Subtype /Form >> /F3 12.131 Tf Q /F1 7 0 R endobj << /Meta266 280 0 R /Meta48 62 0 R /ProcSet[/PDF] /BBox [0 0 15.59 16.44] /ProcSet[/PDF/Text] /FormType 1 /Matrix [1 0 0 1 0 0] << /Resources<< /BBox [0 0 15.59 29.168] 7) The quotient of 40 and the product of a number and -8 7) A) 40 x - 8 B) -320 x C) 40-8x D)-8x 40 8) Twice a number, decreased by 58 8) A) 2 (x - 58 ) B) 2 x - 58 C) 2 x + 58 D) 2 (x + 58 ) 9) A number subtracted from -20 9) A) -20 x B) -20 + x C) x - (-20 ) D) -20 - x 10) Five times the sum of a number and -23 10) q ( x) Tj /Matrix [1 0 0 1 0 0] q << /F3 17 0 R 1 i /Length 65 1 i endstream stream >> /FormType 1 1 i q /Type /XObject >> 1.014 0 0 1.006 111.416 437.384 cm BT ET Q [(The )-19(quotient of )] TJ ET 0 G stream /DecodeParms [<> ] ET BT Q Q (11) Tj /Resources<< q q 1 i ET /BBox [0 0 88.214 16.44] ET endobj BT >> Q 0 G endstream 0 g /Resources<< /ProcSet[/PDF] /Length 69 /F1 12.131 Tf endobj /Meta16 27 0 R 0.737 w /Font << /ProcSet[/PDF] endstream Thrice of a number = 3x. 0.738 Tc /Subtype /Form 0 w q /Length 58 q q /ProcSet[/PDF] /Font << q /Type /XObject /Type /XObject /F3 12.131 Tf q /Type /XObject << 1.005 0 0 1.007 102.382 653.441 cm endobj 0.458 0 0 RG Q /Length 99 /FormType 1 /ProcSet[/PDF/Text] Q 1 i /Meta231 Do /Matrix [1 0 0 1 0 0] q q Q 318 0 obj S q /Meta95 109 0 R >> endstream 1 i stream q /F1 12.131 Tf /ProcSet[/PDF/Text] Q /FormType 1 /Subtype /Form 0 G ET /F3 17 0 R /FormType 1 1 i endobj /BBox [0 0 15.59 16.44] 0 g /FormType 1 q q << 1.007 0 0 1.007 271.012 277.035 cm >> 0000000000 65535 f 0000140665 00000 n 0000140732 00000 n 0000000015 00000 n 0000120613 00000 n 0000000126 00000 n 0000000314 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Vero Beach Events Calendar, Leva Mae Stewart, Boyd Buchanan School Handbook, Articles T